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X²-x-12=0

Describe the number and types of roots using the discriminant
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asked
User Cmwright
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8.5k points

1 Answer

4 votes

Answer:

2 real roots

Explanation:

The discriminant is b^2 -4ac where ax^2 +bx -c

If b^2 -4ac > 0 we have 2 real roots

b^2 -4ac = 0 we have 1 real root

b^2 -4ac < 0 we have 2 complex roots

x²-x-12=0

a =1 b=-1 c = -12

(-1)^2 - 4(1)*(-12)

1 +48

49 > 0

2 real roots

answered
User Wymli
by
7.7k points

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