What is an equation of the line that passes through the points ( −4 , − 6 ) and (4,4)?

Question

asked Mar 3, 2020 16.5k views

2 Answers

Rmcc · Answer 1 · 2020-03-04T18:31:39+0000

Answer:

y = (5)/(4) x -1

Explanation:

Find the slope of this line by using the slope formula:
(y_2-y_1)/(x_2-x_1) . Substitute both given points into this formula.

$((-6)-(4))/((-4)-(4)) \rightarrow(-10)/(-8) \rightarrow(-5)/(-4) =(5)/(4)$

The slope of the line is 5/4. Now this can be plugged into point-slope form since we have the point and the slope of the line.

Use any pair of given points, I'll be using (4,4).

Point-slope form:
y-y_1=m(x-x_1)

Substitute 4 for
x_1 , 4 for
y_1 , and 5/4 for m.

y-(4)=(5)/(4) (x-(4))

Simplify this equation.

$y-4=(5)/(4) (x-4)\rightarrow y-4=(5)/(4) x-5\rightarrow y = (5)/(4) x -1$

The equation in slope-intercept form of the line is
y = (5)/(4) x -1 .