Question

how many moles of ammonium chloride are required for a complete reaction with 420 mol of calcium hydroxide

Answer 1

3 KOH + H3PO3 = K3PO4 + 3 H2O

moles KOH = 26.5 g/56.1 g/mol=0.472

moles K3PO4 = 0.472/3 =0.157