Question

A bag contains 22 red marbles, 33 green marbles, and 44 blue marbles. If we choose a marble, then another marble without putting the first one back in the bag, what is the probability that the first marble will be green and the second will be red?

Answer 1

`(11)/(147)`

Explanation:

P(green ) =
`(33)/(99)` =
`(1)/(3)`

Without replacement the total number of marbles = 98

P(red) =
`(22)/(98)` =
`(11)/(49)`

P(green and red ) =
`(1)/(3)` ×
`(11)/(49)` =
`(11)/(147)`