Question

I need help fast !!Please reply asap

Answer 1

A

Explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

To calculate m use the slope formula

m = ( y₂ - y₁ ) / (x₂ - x₁ )

with ( x₁, y₁ ) = (0, - 3) and (x₂, y₂ ) = (4, 0)

m =
`(0+3)/(4-0)` =
`(3)/(4)`

Given a line with slope m then the slope of a line perpendicular to it is

`m_(perpendicular)` = -
`(1)/(m)` = -
`(4)/(3)`

y = -
`(4)/(3)` x + c ← is the partial equation

To find c substitute (4, - 6) into the partial equation

- 6 = -
`(16)/(3)` + c ⇒ c = - 6 +
`(16)/(3)` = -
`(2)/(3)`

y = -
`(4)/(3)` x -
`(2)/(3)` ← in slope- intercept form

Multiply all terms by 3

3y = - 4x - 2 ( add 4x to both sides )

4x + 3y = - 2 ← in standard form

Answer 2

4x+3y= -2

Explanation:

rise over run

right or up = positive

left or down = negitive

you go up 3

you go right 4

4-6= -2

4x+3y= -2