Question

Find the area of a square with a side length of 1/4 in.

Answer 1

`\bf \textit{area of a square}\\\\ A=s^2~~ \begin{cases} s=side\\[-0.5em] \hrulefill\\ s=(1)/(4) \end{cases}\implies A=\left( \cfrac{1}{4} \right)^2\implies A=\cfrac{1^2}{4^2}\implies A=\cfrac{1}{16}~in^2`