How many moles of potassium hydroxide are needed to completely react with 2.94 moles of aluminum sulfate according to the following equation:

Question

asked Feb 6, 2020 3.1k views

1 Answer

OneWorkingHeadphone · Answer 1 · 2020-02-11T02:19:45+0000

Answer:- Third choice is correct, 17.6 moles

Solution:- The given balanced equation is:

$Al_2(SO_4)_3+6KOH\rightarrow 2Al(OH)_3+3K_2SO_4$

We are asked to calculate the moles of potassium hydroxide needed to completely react with 2.94 moles of aluminium sulfate.

From the balanced equation, there is 1:6 mol ratio between aluminium sulfate and potassium hydroxide.

It is a simple mole to mole conversion problem. We solve it using dimensional set up as:

2.94molAl_2(SO_4)_3((6molKOH)/(1molAl_2(SO_4)_3))

= 17.6 mol KOH

So, Third choice is correct, 17.6 moles of potassium hydroxide are required to react with 2.94 moles of aluminium sulfate.