Question

Which parabola will have one real solution with the line y = x - 5?

Answer 1

y=x^2+7x+4

Explanation:

because the sign before x^2 is positive, the graph would concave up, if there's only one intercept, it has to be the vertex. the vertex is the critical point.

solve every make the derivative of each function equals zero, you get the x where the vertex shall be, then get this"x" into y=x-5 see if the y in y=x-5 is equal to y=x^2+6x+9 or other options.

let me give u an example.

for y=x^2+x-4, the critical point shall be 2x+1=0,x=-1/2, and the y is -4.25,

if you plug x=-1/2 into y=x-5, it's -5.5, -5.5 doesn't equal to -4.25

Answer 2

D

Explanation:

y = x2 + 7x + 4