Question

if an object 18mm high is placed 12mm from a diverging lens and the image is formed 4mm in front of the lens what is the height of the image

Answer 1

To solve this problem we use an amplification formula for divergent lenses

`M = (i)/(o) = (h')/(h)`

Where:

i: distance of the image to the lens

o: Distance from the object to the lens

h = height of the object

h '= height of the image

`M = (4mm)/(12mm) = (h')/(18mm)`

`h'= 18mm(4mm)/(12mm)`

h '= 6 mm

The height is 6 mm