Question

What is the exact value of the exponential equation 17+e7x=33 ?

b. x=ln16 /33
c. x=ln16 /7

Answer 1

hello :

e^7x = 33 - 17

e^7x = 16

7x = ln16

x= ln16/7 .... ( answer : c )

Answer 2

c

Explanation:

using the law of logarithms

log
`x^(n)` ⇔ nlogx

given 17 +
`e^(7x)` = 33 ( subtract 17 from both sides )

`e^(7x)` = 16 ( take the ln of both sides )

ln
`e^(7x)` = ln16

7xlne = ln16 ← lne= 1

7x = ln16 ( divide both sides by 7 )

x =
`(ln16)/(7)` → c