Question

The diagram below represents the net of a triangular prism. What is the surface area of the triangular prism?

Answer 1

(C)

Explanation:

The diagram is divided ninto 5 parts that is rectangles ABCD, CHGD, GFEH and triangles CIH and DGJ.

Area of rectangle ABCD=
`l{*}b`

=
`12{*}6=72cm^(2)`

Area rectangle CDHG=
`l{*}b`

=
`12{*}8=96cm^(2)`

Area rectangle HGFE=
`l{*}b`

=
`10{*}12=120cm^(2)`

Area of triangles CIH and DIG=
`2{*}(1)/(2){*}b{*}h`

=
`6{*}8=48cm^(2)`

Surface area of the triangular prism=Area of rectangle ABCD+Area rectangle CDHG+Area rectangle HGFE+Area of triangles CIH and DIG

=
`72+96+120+48=336cm^(2)`

Hence, option C is correct.