Question

Can one of you help with these questions, please?

Thanks

Answer 1

(13)

`f(3)=6`

(47)

`x\leq -5`

Or

`x\geq -2`

(48)

`x<-7`

Or

`x\geq 1`

Explanation:

(13)

we are given graph of f(x)

we can locate x=3 on graph

so, we get

`f(3)=6`

(47)

we are given

`x+7\leq  2`

Subtract both sides by 7

`x+7-7\leq  2-7`

`x\leq -5`

Or

`(x+14)/(4) \geq 3`

Firstly, we will multiply both sides by 4

`4* (x+14)/(4) \geq 4* 3`

`x+14 \geq 12`

Subtract both sides by 14

`x+14-14 \geq 12-14`

`x\geq -2`

now, we can locate it on number line

we get

(48)

we are given

`3x+5<-16`

Subtract both sides by 5

`3x+5-5<-16-5`

`3x<-21`

Divide both sides by 3

`x<-7`

Or

`-5x-8\leq -13`

Add both sides by 8

`-5x-8+8\leq -13+8`

`-5x\leq -5`

Divide both sides by -5

we get

`x\geq 1`

now, we can draw on number line

and we get