Question

How many grams of nitrogen are contained in a sample of C4H9N302 that also

contains 9.42 x 1024 hydrogen atoms?

Answer 1

Empirical formula = mol ratio

mol H = 9.42 x 10²⁴ : 6.02 x 10²³ = 15.648

mol N = 3/9 x 15.648 = 5.216

mass N = 5.216 x 14 g/mol =73.024 g