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Write the equations for the line parallel and the line perpendicular to the given line passing through the given point.

Write the equations for the line parallel and the line perpendicular to the given-example-1

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Answer:

10. y=2x+1 y = -1/2x +1

11. y=-1/3x +6 y = 3x -4

12. y=-5x-18 y=1/5x + 14/5

Explanation:

To write the equation of a line we must have a slope and a point. To find the slope, we use the slope from the equations for parallel lines and modify it for perpendicular lines.

10. Use the point-slope form to write the equation, then simplify and convert into the slope intercept form. The slope here is 2. The parallel slope is 2 and the perpendicular slope is the negative reciprocal or -1/2.

Parallel Perpendicular

(y-1)=2(x-0) (y-1)==-1/2(x-0)

y-1=2x y-1 = -1/2 x

y=2x+1 y = -1/2x +1

11. Use the point-slope form to write the equation, then simplify and convert into the slope intercept form. The slope here is -1/3. The parallel slope is -1/3 and the perpendicular slope is the negative reciprocal or 3.

Parallel Perpendicular

(y-5)=-1/3(x-3) (y-5)=3(x-3)

y-5=-1/3x+1 y-5 = 3x - 9

y=-1/3x +6 y = 3x -4

12. Use the point-slope form to write the equation, then simplify and convert into the slope intercept form. The slope here is -5. The parallel slope is -5 and the perpendicular slope is the negative reciprocal or 1/5.

Parallel Perpendicular

(y-2)=-5(x--4) (y-2)=1/5(x--4)

y-2=-5(x+4) y-2 = 1/5(x +4)

y-2=-5x -20 y-2 = 1/5x +4/5

y=-5x-18 y=1/5x + 14/5


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User Jaeeun Lee
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