Question

The San Francisco earthquake of 1906 occurred along what fault? A. the San Francisco fault B. the California fault C. the San Andreas fault D. the Pacific fault

Answer 1

The correct answer is C. The San Francisco earthquake of 1906 occurred along the San Andreas fault.

Step-by-step explanation:

The 1906 San Francisco earthquake was a major earthquake disaster that hit San Francisco and Northern California's coast on April 18, 1906. The most widely accepted theory of the quake's strength suggests a momentum magnitude of 7.8. The epicenter was at sea, about three kilometers from the city.

But it was not only the earthquake that destroyed the city, but several heavy fires erupted as a result of the earthquake. The fire soon caused explosions in gas pipelines. Then fire spread uncontrollably among the damaged buildings in the city. The fires became even worse when many residents set fire to their own earthquake-damaged houses. This was done as a result of the fact that home insurance only covered damage caused by fires, not earthquakes.

The disaster claimed around 3,000 casualties, and more than a quarter of a million people became homeless. The damage was estimated at the equivalent of $ 10.5 billion.

Answer 2

The correct answer is - C. the San Andreas fault.

San Francisco, as most of the western of California, is lying in close proximity to the San Andreas fault. This fault is a continental transform fault that is formed as a result of the transform boundary between the Pacific plate and the North American plate, with a small plate lying in between them. Because of the horizontal movement of the plates and the pressure they cause to one another, there's constant adjustments inside the crust, and that contributes to lot of earthquakes in the region. One of those earthquakes was the San Francisco earthquake of 1906, a very strong and devastating earthquake, often considered as the worst earthquake in the history of the United States.