Question

Find the solution set for this equation:
-a2+4a=0
(Separate the two values with a comma)

Answer 1

`\quad \quad \quad \quad\huge \tt \pink ❆ AnSweR \pink ❆`

`\quad\quad \tt-a^2+4a= 0`

`\: \: \: \: \: \: \: \: \: \: \:`

`\quad\quad\tt⇢-1(a^2 - 4a) = 0`

`\: \: \: \: \: \: \: \: \: \: \:`

`\quad\quad\tt⇢-1(a-4)a = 0`

`\: \: \: \: \: \: \: \: \: \: \:`

`\quad\quad\tt⇢a-4=0`

`\: \: \: \: \: \: \: \: \: \: \:`

`\quad\quad\tt⇢a = 0`

-----------------------------------------------------------

`\boxed{ \tt \blue{a = 0}}`

`\boxed{ \tt\blue{a = 4}}`

Answer 2

`\quad \huge \quad \quad \boxed{ \tt \:Answer }`

`\qquad \tt \rightarrow \: \{ 0,4 \}`

____________________________________

`\large \tt Solution \: :`

`\qquad \tt \rightarrow \: - {a}^(2) + 4a = 0`

`\qquad \tt \rightarrow \: - ( {a}^(2) - 4a) = 0`

`\qquad \tt \rightarrow \: {a}^(2) - 4a = 0`

`\qquad \tt \rightarrow \:a(a - 4) = 0`

The two cases are :

• a = 0

or

• a -4 = 0, that leads to a = 4

We can conclude :

`\qquad \tt \rightarrow \:solution \: (a) = \{ 0,4\}`

Answered by : ❝ AǫᴜᴀWɪᴢ ❞