Question

Someone please help me out with this problem T-T I'm begging

Answer 1

Label the vertices of the quadrilateral A, B, C, D. Angle C is supplementary to the angle of measure 60 degrees, so its own measure is 120 degrees.

AD and BC are parallel, as are AB and CD, so ABCD is a parallelogram. This means angle A also has measure 120 degrees. The angle adjacent to the one with measure
`3x`, part of angle A, then has measure
`120^\circ-3x`.

The three angles above the line through vertex A are supplementary, so we have

`2x+90^\circ+(120^\circ-3x)=180^\circ`

`\implies210^\circ-x=180^\circ`

`\implies x=30^\circ`