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What is the equation of the line perpendicular to 3x+y= -8 x y that passes through ( 3, 1) ? Write your answer in slope-intercept form. Show your work.

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User BenMQ
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2 Answers

2 votes

Hello there,

What is the equation of the line perpendicular to 3x+y= -8 x y that passes through ( 3, 1) ? Write your answer in slope-intercept form. Show your work.

Answer: y= 1/3x



answered
User Bob Monteverde
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8.5k points
0 votes

Answer:

y= 1/3x

Explanation:

To find the slope, convert the standard form of the equation into slope intercept form, y=mx+b.

3x-+y=-8

y=-3x-8

The slope is -3 and the slope of the new line will be 1/3 because the negative reciprocal creates a perpendicular line. Use the point-slope form to write the equation, then simplify and convert into the slope intercept form.

(y-1)=1/3(x-3)

y-1=1/3x-1

y=1/3x+0

y= 1/3x

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