Question

for the simple harmonic motion equation d = 9cos(pi/2)(t), what is the maximum displacement from the equilibrium position ?

Answer 1

Answer: 9

Explanation:

1. You know that the simple harmonic motion equation is:

`d=9cos(pi/2)(t)`

2. You have the following trigonometric function of cosine:

`y=acos (b(x-c)+d`

Where a is the amplitude, or the maximum displacement.

2. Therefore, the maximum displacement from the equilibrium position of the equation given in the problem is 9.

Answer 2

The maximum displacement from the equilibrium position is 9

Explanation:

We are given

equation for the simple harmonic motion equation

`y=9cos((\pi)/(2)t)`

we can use trig formula

`y=Acos(Bt)`

The maximum value of this equation is always A

So, firstly, we will compare and find A

A=9

so,

The maximum displacement from the equilibrium position is 9