Question

Suppose a 2.0kg bird is flying at a speed of of 1m/s. It’s kinetic energy would be what?

Answer 1

As we know that the formula of kinetic energy will be

`KE = (1)/(2) mv^2`

now here we know that

m = 2 kg

v = 1 m/s

so from the above equation we have

`KE = (1)/(2)(2)(1^2)`

`KE = 1 J`