Question

Compute the permutation. A chemist has eight test tubes to examine. In how many orders can he do this examination? 16,777,216 20,160 40,320

Answer 1

40,320

Explanation:

Answer 2

40,320

Explanation:

He can pick any one of the eight for the first examination.

He can pick any one of the remaining 7 for the 2nd examination.

He can pick any one of the remaining 6 for the 3rd examination.

...

He can pick any one of the remaining 2 for the 7th examination.

There's one left for the 8th examination.

Thus, there are 8×7×6×5×4×3×2×1 = 8! = 40,320 different possible orders in which the tubes can be examined.