A linear function has a slope of 5/2 and passes through the point 0,6 . What is the equation of the line?

Question

asked Feb 13, 2020 170k views

2 Answers

Adangel · Answer 1 · 2020-02-14T13:45:58+0000

y - Y1 = m(x - X1)

y - 6 = 5/2(x - 0) --- POINT SLOPE FORM

y - 6 = 5/2x - 0

+ 6 + 6

y = 5/2x + 6 --- SLOPE INTERCEPT FORM

-5/2x -5/2x

-5/2x + y = 6 --- STANDARD FORM

Hope this helps you!!! :)