asked 164k views
4 votes
If $m \Diamond n = (m^2 - n) \div n$ for all real numbers $m$ and $n$, where $n \\eq 0$, what is the value of $6 \Diamond 3$?

asked
User Roy J
by
7.7k points

1 Answer

3 votes

By definition of ◇, you have

6 ◇ 3 = (6² - 3)/3 = (36 - 3)/3 = 33/3 = 11

answered
User Emeka
by
8.3k points
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