Question

What is the correct answer?

Answer 1

Given:

Dividend =
`3x^3-3x^2-4x+3`

Divisor =
`x+3`

To find:

The quotient and remainder.

Solution:

On dividing
`3x^3-3x^2-4x+3` by
`x+3`, we get

`x+3\ |\overline{3x^3-3x^2-4x+3} |\ 3x^2-12x+32`

`3x^3+9x^2`

`\underline{(-)\quad (-)\quad \quad \quad \quad \quad }`

`-12x^2-4x+3`

`-12x^2-36x`

`\underline{(+)\quad (+)\quad \quad \quad }`

`32x+3`

`32x+96`

`\underline{(-)\quad (-)\quad }`

`\underline{\quad -93\quad }`

Here,

Quotient =
`3x^2-12x+32`

Remainder =
`-93`

Therefore, the correct option is D.