Question

when 0.15 moles of sodium reacts with 0.30 moles of oxygen what is the moles of the product formed when one reagents is used in excess

Answer 1

0.075 moles of product formed.

Step-by-step explanation:

Given data:

Number of moles of oxygen = 0.30 mol

Number of moles of oxygen = 0.15 mol

Number of moles of product formed = ?

Solution:

Chemical equation:

4Na + O₂ → 2Na₂O

Now we will compare the moles of Na₂O with oxygen and sodium.

Na : Na₂O

4 : 2

0.15 : 2/4×0.15 = 0.075 mol

O₂ : Na₂O

1 : 2

0.30 : 2/1×0.30 = 0.6 mol

Less number of moles of Na₂O are produced by sodium thus it will limit the yield of Na₂O and act as limiting reactant while oxygen is in excess.