asked 235k views
2 votes
What is the slope of a line parallel to the line whose equation is 3x-3y=-453x−3y=−45.

asked
User ChaTho
by
8.5k points

1 Answer

5 votes

Answer:

75.5x is the slope

453x+(-6y)=-45

-6y/-6y= y

-45/-6= 7.5

-453/-6= 75.5

y=7.5+ 75.5x

answered
User SergA
by
8.7k points

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