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Helium decays to form lithium. Which equation correctly describes this decay? Superscript 6 Subscript 2 Baseline Upper H e right arrow Superscript 3 Subscript 3 Baseline Upper L i + Superscript 0 Subscript negative 1 Baseline e Superscript 6 Subscript 2 Baseline Upper H e right arrow Superscript 6 Subscript 3 Baseline Upper H + Superscript 0 Subscript negative 1 Baseline e Superscript 6 Subscript 2 Baseline Upper H e right arrow Superscript 6 Subscript 3 Baseline Upper L i + Superscript 0 Subscript negative 1 Baseline e Superscript 6 Subscript 2 Baseline Upper H e right arrow Superscript 6 Subscript 3 Baseline Upper L i + Superscript 0 Subscript 1 Baseline e

asked
User Fonfonx
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8.5k points

2 Answers

3 votes

Answer:

C

Step-by-step explanation:

Edge 2020

answered
User Tacoshy
by
8.4k points
3 votes

Answer:

Superscript 6 Subscript 2 Baseline Upper H e right arrow Superscript 6 Subscript 3 Baseline Upper L i + Superscript 0 Subscript negative 1 Baseline e

Step-by-step explanation:

Helium decays by beta emission, in beta emission, the mass number of the parent and daughter nuclei are the same but the atomic number of the daughter nucleus increases by one hence it is found one place to the right of its parent in the periodic table.

Having said this, the decay of Helium to lithium may be written as follows;

6/2He -> 6/3Li + 0/-1e

answered
User Frasertweedale
by
7.7k points
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