Question

How many molecules are present in 187 grams of XeF4

Answer 1

There are 5.43 x 10²³ present in 187 grams of XeF₄

Further explanation

The mole is the number of particles(molecules, atoms, ions) contained in a substance

1 mol = 6.02.10²³ particles

Can be formulated

N=n x No

N = number of particles

n = mol

No = Avogadro's = 6.02.10²³

Moles can also be determined from the amount of substance mass and its molar mass

`\tt n(mol)=(mass(m))/(MW)`

mass of XeF₄ = 187 g

mol XeF₄ (MW=207,2836 g/mol) :

`\tt mol=(187)/(207,2836 g/mol)=0.902`

Number of molecules :

`\tt N=0.902* 6.02* 10^(23)\\\\N=5.43* 10^(23)`