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The area of a rectangle is 8X^3+6^X+^2-10x. The width of the rectangle is 2x. Find the length of the rectangle. Please help.

The area of a rectangle is 8X^3+6^X+^2-10x. The width of the rectangle is 2x. Find the length of the rectangle. Please help.
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1 vote
The area of a rectangle is 8X^3+6^X+^2-10x. The width of the rectangle is 2x. Find the length of the rectangle.

Please help.

The area of a rectangle is 8X^3+6^X+^2-10x. The width of the rectangle is 2x. Find-example-1
asked
User Siur
by
8.5k points

1 Answer

2 votes

Answer:

4x^2 + 3x - 5

Explanation:

Area / width = length

(8x^3+6x^2-10x)/2x =

4x^2 + 3x - 5

answered
User Etienne Maheu
by
8.4k points
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