Question

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Answer 1

Explanation:

radius=10cm

<A0B=90°

Length of arc AB,

`10 * (\pi)/(2 ) = 5 * 3.14 = 15.4cm`

`perimeter \: of \: quadrant = \: 10 + 10 + 15.4 = 35.4cm`

Area of quadrant=

`(90)/(360 ) * 3.14 * {10 }^(2) = 78.5cm ^(2)`

Answer 2

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