Question

Find the slope of the line that passes through (2, 1) and (6,2).

Answer 1

`\boxed{m = (1)/(4)}`

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Explanation:

Use the form below

`\boxed{\boxed{m = (y_2 - y_1)/(x_2 - x_1) }}`

Where

• 
  `m` is a slope
• 
  `(x_1,~y_1)` and
  `(x_2,~y_2)` are the point of the line

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So, the slope is

`(2,~ 1) \to x_1 = 2~and~y_1 = 1`

`(6,~ 2) \to x_2 = 6~and~y_2 = 2`

.

`m = (2-1)/(6-2)`

`m = (1)/(4)`

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Happy to help:)

Answer 2

`\boxed {\boxed {\sf m=(1)/(4)}}`

Explanation:

The slope of a line can be found using the slope formula or dividing the change in y by the change in x.

`m=(y_2-y_1)/(x_2-x_1)`

where (x₁, y₁) and (x₂, y₂) are the points the line passes through.

We are given the points (2,1) and (6,2). Therefore:

`x_1=2 \\y_1= 1\\x_2= 6\\y_2=2`

Substitute the points into the formula.

`m=(2-1)/(6-2)`

Solve the numerator.

• 2-1=1

`m=(1)/(6-2)`

Solve the denominator

• 6-2=4

`m=(1)/(4)`

This fraction cannot be reduced further, so it is the slope. It can be written as a decimal too:

`m= 0.25`

The slope of the line is 1/4 (0.25)