Question

Calculate the pH of 15 mL of water after 0.15 mL of 1 M HCl is added.

Answer 1

≈2.004

Step-by-step explanation:

Using the dilution formula which is,

M1V1=M2V2

(1)(0.15)=M2(15.15)

M2=9.90×10^-3

pH formula: -log(H+)

= -log(9.90×10^-3)

=2