Question

A train accelerated from 20km/hr to 80km/hr in 4 minutes. How much distance does

it cover in this period? Assume that the tracks are straight?

Answer 1

S = V0 t + 1/2 a t^2

a = (V2 - V1) / t = (80 - 20) km/hr / .067 hr = 900 km/hr^2

S = 20 km/hr * 067 hr + 1/2 * 900 * .067^2 km = 3.34 km