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What happens to a 8 L volume of gas as you love a pressure of 3 atm to 4 atm? Use the correct gas law to determine the new volume

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User Saddie
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Assuming pressure is held constant,


(8)/(3)=(V_(2))/(4)\\\\V_(2)=4\left((8)/(3) \right) \approx \boxed{10.7 \text{ L}}

What happens to a 8 L volume of gas as you love a pressure of 3 atm to 4 atm? Use-example-1
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User Coldfused
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