How do you solve this problem:((2-b)^2)/((b-2)^2)

Question

How do you solve this problem:
`((2-b)^2)/((b-2)^2)`

Answer 1

Explanation:

`\frac{ {(2 - b)}^(2) }{{(b - 2)}^(2) }`

`((2-b)(2-b))/((b - 2)(b - 2))`

`\frac{4 - 2b - 2b + {b}^(2) }{ {b}^(2) - 2b - 2b + 4 }`

`\frac{4 - 4b + {b}^(2) }{ {b}^(2) - 4b + 4 }`

(Rearrange)

`\frac{ {b}^(2) - 4b + 4 }{ {b}^(2) - 4b + 4 }`

Then eliminate same sign above and below.

since they all have pair, therefore the equation is equal to 1.

(If anybody did any answer please delete this I feel so embarrassed haha)

I hope you understand and let me know whether this helps :)