Question

F(x)= 2x^2+4x+10
G(x)= 3x-11
H(x)= 3x^3+x^2-21

The value of H(F(G(2)))

Answer 1

Explanation:

H(F(6-11))

H(F(-5))

H(F(50-20+10))

H(40))

3×(40^3)+40^2-21

=193579