Question

Suppose an automobile has a kinetic energy

of 2300 J.
When it moves with nine times the speed,
what will be its kinetic energy?
Answer in units of J.

Answer 1

`KE_(new)=186300 J`

Step-by-step explanation:

Given:

`KE=2300J`
`n=9`

`v_(new)=n*v_(old)`

`(KE_(new))/(KE_(old))=(v^2_(new))/(v^2_(old))=((n*v_(old))^2)/(v^2_(old))=n^2`

`KE_(new)=n^2KE_(old)`

`KE_(new)=(9)^2(2300)`

`KE_(new)=186300 J`

Scientific notation

`KE_(new)= 1.863*10^5 J`

Hope it helps