asked 153k views
4 votes
. An object is launched straight up into the air. It is launched from a height

of H feet off the ground. Its height H, in feet, at t seconds is given by the
equation H = -8t^2 + 40t + 18. Find all times t that the object is at a height
of 50 feet off the ground.

1 Answer

4 votes

Answer:

H=24

Explanation:

answered
User Jms Bnd
by
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