Question

Which equation describes a line perpendicular to line r that passes through the point (3,-6) x-3y=21, 3x+y=3, 3x-y=15, 3x-y=3

Answer 1

See Explanation

Explanation:

Missing in the question is the slope of line r.

We'll assume that the slope (m) of line r is

`m = -(1)/(3)`

When two lines are perpendicular, their slope are related in:

`m_2 = -1/m_1`

`m_2 = -1/(-1)/(3)`

`m_2 = -1 * -3`

`m_2 = 3`

The equation of the (3,-6) is:

`y - y_1 = m(x - x_1)`

Where

`(x_1,y_1) = (3,-6)`

So:

`y - (-6) = 3(x - 3)`

`y +6 = 3x - 9`

Make y the subject

`y = 3x - 9 - 6`

`y = 3x - 15`

Please note that this answer might be incorrect to you based on the assumed value. However, the step will guide you in solving similar questions