Question

Tinky Winky is 2 years younger than Laa Laa. If the product of Tinky's and Laa Laa's ages is equal to 1 less than 5 times the sum of their ages, how old is Tinky?

Answer 1

Solution:-

Let

Tinky's age=x

Laa's age=x+2

According to the question

`\qquad\quad {:}\longmapsto\sf 5 (x+x+2)-1=x (x+2)`

`\qquad\quad {:}\longmapsto\sf 5(2x+2)-1=x^2+2x`

`\qquad\quad {:}\longmapsto\sf 10x+5-1=x^2+2x`

`\qquad\quad {:}\longmapsto\sf 10x+4=x^2+2x`

`\qquad\quad {:}\longmapsto\sf 10x-2x+4=x^2`

`\qquad\quad {:}\longmapsto\sf x^2=8x+4`

`\qquad\quad {:}\longmapsto\sf x^2-8x-4=0`