Question

Solve the following triangle. Round side measure to the nearest tenth and angle measure to the nearest degree:

Answer 1

Answer:
`AB=4.7, BC=8.8, \angle C=28^(\circ)`

Explanation:

As angles in a triangle add to 180 degrees,

`\angle C=180^(\circ)-90^(\circ)-62^(\circ)=\boxed{28^(\circ)}`

We know that:

`\sin 62^(\circ)=(BC)/(10)\\\\BC=10\sin 62^(\circ) \approx \boxed{8.8}`

Similarly,

`\cos 62^(\circ)=(AB)/(10)\\\\AB=10\cos 62^(\circ) \approx \boxed{4.7}`