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In the equation (x-3)2+(y-2)2=16, the center of the circle is...

In the equation (x-3)2+(y-2)2=16, the center of the circle is...
asked 72.6k views
4 votes
In the equation
(x-3)2+(y-2)2=16, the center of the circle is...

asked
User Andy Heard
by
8.2k points

1 Answer

5 votes

Answer:

The center circle of this question is (2,3)

answered
User Monique De Haas
by
8.3k points
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