Question

g During the contraction of the heart, 65 cm3 blood is ejected from the left ventricle into the aorta with a velocity of approximately 98 cm/s. The blood volume traverses the aortic arch, exiting with the same speed but opposite direction. Assume the mass density of the blood is 1060 kg/m3 blood, the aortic arch remains stationary, and that the heart rate is 61 bpm. What is the average force exerted by the blood on the wall of the aorta.

Answer 1

The force is
`F = 0.1441 \ N`

Step-by-step explanation:

From the question we are told that

The volume of blood ejected is
`V_b = 65cm^3 = 65*10^(-6) \ m^3`

The velocity of the ejected blood is
`v = 98 cm/ s = 0.98 \ m/s`

The mass density of blood is
`\rho = 1060 \ kg/m^3`

The heart rate is
`R = 61 bpm(beats \ per \ miunite) = (61)/(60) = 1.0667\ bps`

Generally the average force exerted is mathematically represented as

`F = 2 * \rho * V_b * R * v`

=>
`F = 2 * 1060 * (65*10^(-6)) *1.0667 * 0.98`

=>
`F = 0.1441 \ N`