Question

What is the perimeter of this triangle?

Answer 1

Answer:
`a+b+\sqrt{a^(2)+b^(2)}`

Explanation:

The distance from (0,b) to (0,0) is b.

The distance from (0,a) to (0,0) is a.

Using the Pythagorean theorem, the distance from (0,b) to (a,0) is
`\sqrt{a^(2)+b^(2)}`

So, the perimeter is
`\boxed{a+b+\sqrt{a^(2)+b^(2)}}`