Question

The area of a rectangle is 20x^6y^4. The length of the rectangle is x^2y^3. What is the width of the rectangle?

Answer 1

`Width\ of\ the\ rectangle\ is\ 20x^4y`

Explanation:

`We\ know\ that,\\Area\ of\ a\ rectangle=Length*Width\\Here,\\Let\ the\ width\ of\ the\ rectangle\ be\ b\\20x^6y^4=x^2y^3b\\b=(20x^6y^4)/(x^2y^3) \\b=20x^((6-2))y^((4-3))\\b=20x^4y`