Question

5. Given that 2x+329, the range of values of x is
(1 Point)​

Answer 1

The range of 2x+329:

`\mathrm{Range\:of\:}2x+329:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:<f\left(x\right)<\infty \\ \:\mathrm{Interval\:Notation:}&\:\left(-\infty \:,\:\infty \:\right)\end{bmatrix}`

Explanation:

Given the expression

`2x+329`

We know that range is termed as the set of values of the dependent variable for which a function is defined.

• We also know that the range of polynomials with odd degree is all the real numbers.

i.e.
`-\infty \:<f\left(x\right)<\infty \:`

The given expression is a polynomial with an odd degree. Hence, the range of this expression will be all the real numbers.

Thus, the range of 2x+329:

`\mathrm{Range\:of\:}2x+329:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:<f\left(x\right)<\infty \\ \:\mathrm{Interval\:Notation:}&\:\left(-\infty \:,\:\infty \:\right)\end{bmatrix}`