Question

An aqueous solution of potassium hydroxide is standardized by titration with a 0.187 M solution of nitric acid. If 22.7 mL of base are required to neutralize 29.4 mL of the acid, what is the molarity of the potassium hydroxide solution?

Answer 1

Step-by-step explanation:

29.4 mL of nitric acid having molarity of .187M reacts with 22.7 mL of potassium hydroxide .

moles contained in nitric acid solution

= .0294 x .187 moles

= 5.5 x 10⁻³ moles

This must have been reacted with same amount of moles of base

moles of sodium hydroxide in 22.7 mL of solution = 5.5 x 10⁻³ moles

molarity of base solution = 5.5 x 10⁻³ / 22.7 x 10⁻³

= .24 M .