Question

The position of a train at a time 2 seconds is 100m from a station. Suppose its velocities at the end of 2 seconds and at the end of 10 seconds are 5m/s and 20m/s respectively. Find the position of the train at the end of 10 seconds.

Answer 1

vf²=vi²+2ad

5²=0+2a.100

a=0.125 m/s²

20²=0+2 x 0.125 x d

400 = 0.25d

d = 1600 m