Question

If x=-7 is a root of the equation x^2+kx+49=0, then k=​

Answer 1

`k=14`

Explanation:

Given:

`x^(2)+kx+49 = 0`

`x = -7`

Substitution can be used to find the value of
`k`:

`(-7)^(2)+(-7)k+49 = 0`

`49-7k+49 = 0`

`98 -7k = 0`

`k = 14`

Hope this helps :)