Question

Question 2 options: A consumer advocate group selects a random sample of 205 snack foods and finds that 174 of them contain more fat grams than what is indicated in the snack's nutritional information. Create a 90% confidence interval for the population proportion for snack foods that contain more fat grams that what is indicated in the snack's nutritional information.

Answer 1

156 snack foods.

Explanation:

205 - 174 = 31

To find 90% of 174, multiply 174 by 0.90.

174 x 0.90 = 156

The answer is 156 snack foods.